Question

90 by 7 - [ {6 by 11 + (8 by 9 ÷ 4 by 5 )of 7 by 11 } - 5 ]​

Answer 1

Answer:

${\Large{\underline{\underline{\bf{\purple{Question}\: : - }}}}}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} -\bigg[ \bigg\{ \dfrac{6}{11} + \bigg( \dfrac{8}{9} \div \dfrac{4}{5} \bigg) of \: \dfrac{7}{11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\Large{\underline{\underline{\bf{\purple{Solution}\: : - }}}}}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} -\bigg[ \bigg\{ \dfrac{6}{11} + \bigg( \dfrac{8}{9} \div \dfrac{4}{5} \bigg) of \: \dfrac{7}{11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{6}{11} + \bigg( \dfrac{8}{9} \times \dfrac{5}{4} \bigg) of \: \dfrac{7}{11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{6}{11} + \bigg( \dfrac{\cancel{8}}{9} \times \dfrac{5}{\cancel{4}} \bigg) of \: \dfrac{7}{11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{6}{11} + \bigg( \dfrac{2 \times 5}{9 \times 1} \bigg) of \: \dfrac{7}{11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{6}{11} + \bigg( \dfrac{10}{9} \bigg) of \: \dfrac{7}{11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

• ★ Opening "round brackets".

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{6}{11} + \dfrac{10}{9} \times \: \dfrac{7}{11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{6}{11} + \dfrac{10 \times 7}{9 \times 11} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{6}{11} + \dfrac{70}{99} \bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

• ★ Taking LCM of denominators.

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{(6 \times 9) + (70 \times 1)}{99}\bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{54 + 70}{99}\bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \bigg\{ \dfrac{124}{99}\bigg\}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

• ★ Opening "curly brackets".

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \dfrac{124}{99}- 5 \bigg] }}$

$\begin{gathered}\end{gathered}$

• Again, Taking LCM of denominators.

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \dfrac{(124 \times 1) - (5 \times 99)}{99} \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \dfrac{124 - 495}{99} \bigg] }}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \bigg[ \dfrac{ - 371}{99} \bigg] }}$

$\begin{gathered}\end{gathered}$

• ★ Opening "box brackets".

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{90}{7} - \dfrac{ - 371}{99} }}$

$\begin{gathered}\end{gathered}$

• ★ Taking LCM of denominators.

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{(90 \times 99) - ( - 371 \times 1)}{693}}}$

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{8910- ( - 371 )}{693}}}$

$\begin{gathered}\end{gathered}$

• ★ Here, ( - × - = + ).

$\begin{gathered}\end{gathered}$

${\dashrightarrow\sf{\dfrac{9281}{693}}}$

$\begin{gathered}\end{gathered}$

$\bigstar{\underline{\red{\boxed{\bf{Answer = \dfrac{9281}{693}}}}}}$

∴ The answer is 9281 by 693.

$\begin{gathered}\end{gathered}$

${\Large{\underline{\underline{\bf{\purple{Learn \: More}\: : - }}}}}$

BODMAS :

BODMAS rule is an acronym used to remember the order of operations to be followed while solving expressions in mathematics.

It stands for :-

• ↠ B - Brackets,
• ↠ O - Order of powers or roots,
• ↠ D - Division,
• ↠ M - Multiplication 
• ↠ A - Addition,
• ↠ S - Subtraction.

It means that expressions having multiple operators need to be simplified from left to right in this order only.

$\rule{200}2$

BODMAS RULE :

First, we solve brackets, then powers or roots, then division or multiplication (whatever comes first from the left side of the expression), and then at last subtraction or addition.

• ↠ Addition (+)
• ↠ Subtraction (-)
• ↠ Multiplication (×)
• ↠ Division (÷)
• ↠ Brackets ( )

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Answer 2

Step-by-step explanation:

How many families were there in village Morna? 4.