Question

90 c of charge passes in one hour in a copper wire of diameter 1 m capper contains 5.8×10^28 electrons find. (1) current in the wire. (2) drift velocity in the wire​

Answer 1

Answer:

Answer

1 hour 15 minutes=4500 seconds

i=

t

q

i=

4500

90

=0.02 amperes

j=

a

i

j=

(3.14×0.05×0.05)

0.02

j=2.55×10

4

amp/m

2

drift velocity=

ne

j

v(d)=

5.28×10

22

×1.6×10−19

2.55×1000

v(d)=2.69×10

−7