90 gifts were distributed in a party every presented a gift to another how many persons were there in the party
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Step-by-step explanation:
No. Of People be x
Each person would have to give one person a gift=(n-1)
But this would count every given gift as twice. So for equity we would divide whole by 2
A/C to que_
n(n-1)/2=90
(n^2-n)/2=90
n^2-n=180
n^2-n-180=0
n=<-(-1)±root{(1)^2-4×1×(-180)}>/2×1
n=<1+root{1+720}>/2 & <1-root{1+720}>/2
n=<1+26.8>/2 & <1-26.8>/2
n=27.8/2 & -25.8/2
n=13.9 & -12.8
n≠-12.8 because no. Of people can't be -ve
Hence n=13.9≈14 people were there in party
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