90 gm of glucose dissolve in 500 gm of water and density of the solution is 1.8g. find the:--- 1) mole fraction of solute 2) %(w/w) 3) %(w/v) 4) molality
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0
Answer:
Answer
Correct option is
B
0.617m
Molality =
mass of solvent in kg
no of moles of solute
Molar mass of glucose = 180g
Mass of glucose =10
No of moles of glucose =
180
10
=0.0556mol
the solution of glucose in water which is 10% w/W means 10 g of glucose in 100 g of solution
Mass of solvenyt=100-10=90 g =0.090 kg
Molality =
0.090
0.556
=0.617m
Hence, the correct option is B
Answered by
0
Answer:
Molality =
mass of solvent in kg
no of moles of solute
Molar mass of glucose = 180g
Mass of glucose =10
No of moles of glucose =
180
10
=0.0556mol
the solution of glucose in water which is 10% w/W means 10 g of glucose in 100 g of solution
Mass of solvenyt=100-10=90 g =0.090 kg
Molality =
0.090
0.556
=0.617m
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