Question

90 gm of glucose is dissolved in sufficient water to produce 500 ml of solution. If the density of solution
is 1.18 gm/ml. Calculate molality of the solution
(1) 0.5
(2) 1.5
(3) 1
(4) 2.5​

Answer 1

Answer:

option 3 is correct

molality = (weight of solute/ molecular mass of solute )× 1000/ weight of solvent here mass of solute is 90 gm, and glucose molecular mass is 180 and volume of solution is 500 ml and solution density is 1.18 gm/ml , density = mass / volume then mass of solution is 590 gm ..... mass of solution = mass of solute+ mass of solvent then mass of solvent is 500 gm and put the value in molality formula , m= (90/180)× (1000/500 ) after solving molality is 1

Answer 2

Answer:

Here is your answer. Thank you