90 gram glucose (C6H12O6)and 30 gram urea (NH2CONH2) are dissolved in 162 gram water what will the mole fraction of glucose
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mole fraction of glucose=
no. of moles glucose/no.moles of glucose+ no.moles of urea
no. moles of glucose= w/mw
=90/180 (molar mass of glucose=180)
=0.5
no. moles of urea= 30/60(molar mass of urea=60)
=0.5
therefore,
mole fraction of glucose= 0.5/0.5+0.5
=0.5
no. of moles glucose/no.moles of glucose+ no.moles of urea
no. moles of glucose= w/mw
=90/180 (molar mass of glucose=180)
=0.5
no. moles of urea= 30/60(molar mass of urea=60)
=0.5
therefore,
mole fraction of glucose= 0.5/0.5+0.5
=0.5
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Explanation:
0.5 ........................
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