Question

.
90 grams of water and 230 grams of an organic liquid on
mixing gives mole fraction of water in the resulting
solution as 0.5, the molecular weight of the organic liquid
is​

Answer 1

Explanation:

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Answer 2

The molecular weight of the organic liquid is 46 g/mol.

GIVEN

Amount of water in the mixture = 90 grams.

Amount of Organic liquid in the mixture = 230. grams.

Mole fraction of water = 0.5

TO FIND.

The molecular weight of organic liquid

SOLUTION

We can simply solve the above problem as follows.

Mole fraction of water = 0.5

Mole fraction of organic solvent = 1-0.5 = 0.5

Let the moles of the organic liquid be, n1

Moles of the water, n2 = 90/18 = 5

Applying the formula -

$x = \frac{n1}{n1 + n2}$

Where,

x = mole fraction of the organic solvent

n1 = moles of organic liquid

n = moles of water.

Putting the values in the above formula we get,

$\frac{1}{2} = \frac{n1}{n1 + 5}$

5 + n1 = 2n1

n1 = 5 moles.

The molecular weight of the solvent = Given weight/moles.

= 230/5

= 46 g/mol

Hence, The molecular weight of the organic liquid is 46 g/mol.

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