Question

90. In a population in Hardy-Weinberg equilibrium, if the
dominant allele frequency is 0.50, then the frequency of
heterozygotes is
a. 0.10
b. 0.25
c. 0.75
d. 0.50​

Answer 1

Answer

d

0.50

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Answer 2

Answer:

frequency is (d).50

Explanation:

It is given that p=.50

and we know that p+q=1

so, q=1-p

q=1-.50

q=.50

We also know that frequency of heterozygotes is=2pq

So, frequency = 2 × .50 × .50

= .50