Math, asked by akhan76, 1 year ago

90 men can compete a work in 24 days working 8 hours a day. How many men are required to complete the same work in 18 days working 7.5 hours a days

Answers

Answered by shoaika

0

Answer:

Step-by-step explanation:

m1d1h1/w2 =m2d2h2/w2

90×24×8=m2×18x7.5

17280= m2×135

M2=128 so 128 men are required

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