Question

900 kg car is moving at a speed of 20 metre per second along a level road car retarded force required to stop in a distance of 30 metre is

Answer 1

hope it would clear your doubt

Answer 2

Answer:

-6000N

Explanation:

Given:

m= 900kg

u= 20m/s

v= 0

s= 30m

To find: Retarded force

Solution:

According to Newton's Third Law, if object A applies a force to object B, then object B must do the same to object A, but in the opposite direction and with an equal magnitude.

The velocity of a body may rise or fall. When a body's velocity changes, it accelerates. As a result, when a body's velocity increases, the acceleration is said to be positive, and when it drops, it is said to be negative (Retardation). When the body's velocity is reducing, then it is said to be retarded.

For instance, a train is said to be delayed when its speed drops as it approaches a station.

When acceleration has a negative sign, it is called retardation. When the acceleration is negative, the body's velocity declines.

$v^{2} -u^{2} =2as\\0^{2}-20^{2}=(2)(a)(30)\\ \frac{(-20)(20)}{(2)(30)} =a\\a=\frac{-20}{3}$

F=ma

$=(900)(\frac{-20}{3})=-6000N$

Hence the correct answer is -6000N.

A retardation of 2m/s is produced when brakes are applied to a running car.

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Si unit of retardation

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