Question

9000 for 2 years 4 months at 10% per annum compounded annually.
​

Answer 1

$\bf{\huge{Answer}}$

Given Principal Amount= P= 9000

Rates of interest Per annum= i =10%

Time= n =2years 4 months.. or 2 1/3 years

Compound Interest = P[ (1+i)^n - 1]

=9000[ (1+10/100)^2 1/3 - 1]

=9000[(1 + 10/100)^2 (1+ 10/100×3) -1]

=9000[ (1.1)^2 (1.033) - 1]

=9000[1.21 × 1.033 - 1]

=9000[1.25033333293 - 1]

=9000[ 0.25033333293]

= 2253 is the Compound Interest...

Then compounded Amount = Principal Amount + Compound Interest

=9000+ 2253= 11253 is the Compounded amount

Answer 2

Answer:

CA = Rs. 11253

Step-by-step explanation:

Here,

P = Rs. 9000

T = 2yrs 4months

R = 10%

We know,

CA = P(1+R/100)^T (1+ MR/1200)

=9000(1+10/100)^2 (1+ 4*10/1200)

=9000(1+0.1)^2 (1 + 1/30)

=9000(1.1)^2 *31/30

=9000 * 1.21 * 31/30

=Rs. 11253