Math, asked by nia894747, 1 year ago

₹ 9000 for 2 years 4 months at 10% per annum compounded annually​


janhavi5350: plz

Answers

Answered by janhavi5350
8

Answer:

Step-by-step explanation:

Given Principal Amount= P= 9000

Rates of interest Per annum= i =10%

Time= n =2years 4 months.. or 2 1/3 years

Compound Interest = P[ (1+i)^n - 1]

=9000[ (1+10/100)^2 1/3 - 1]

=9000[(1 + 10/100)^2 (1+ 10/100×3) -1]

=9000[ (1.1)^2 (1.033) - 1]

=9000[1.21 × 1.033 - 1]

=9000[1.25033333293 - 1]

=9000[ 0.25033333293]

= 2253 is the Compound Interest...

Then compounded Amount = Principal Amount + Compound Interest

=9000+ 2253= 11253 is the Compounded amount.


janhavi5350: and can you answer my quetion i asked in english sub
nia894747: sure but can you please tell me how 2
nia894747: 2 1/3 camw
nia894747: came
nia894747: don't marathi
janhavi5350: means
janhavi5350: dont marathi?
nia894747: i don't know marathi language
nia894747: sorry
janhavi5350: ok no problem .
Answered by aakusi
6

Answer:

Hey mate here is your answer

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