Question

9000 for 2year 4 month at 10% pe annum compound annually

Answer 1

Answer:

$9000[1+\frac{r}{100} ]{2}$

Step-by-step explanation:

then$for 2 yr\\  p =9000\\r=10%\\a= 9000[1+\frac{10}{100} ]^2\\=9000*\frac{11}{10}* \frac{11}{10} \\=90*121\\=10890\\\\\\for 4 months \\p=10890\\r =10%\\a =10890[1+10/300]\\   = 10890*31/30\\=363*31\\=11253rs\\\\\\ci=a-p\\11253-9000\\2253rs$