Question

₹90000 borrowed at 5.5% p.a. for 3years.find the amount to be paid at the end of third year​

Answer 1

Answer:

Find the simple interest on:

Find the simple interest on:(a) $ 900 for 3 years 4 months at 5% per annum. Find the amount also.

Find the simple interest on:(a) $ 900 for 3 years 4 months at 5% per annum. Find the amount also.Solution:

Find the simple interest on:(a) $ 900 for 3 years 4 months at 5% per annum. Find the amount also.Solution:P = $ 900,

Find the simple interest on:(a) $ 900 for 3 years 4 months at 5% per annum. Find the amount also.Solution:P = $ 900,R = 5% p.a.

Find the simple interest on:(a) $ 900 for 3 years 4 months at 5% per annum. Find the amount also.Solution:P = $ 900,R = 5% p.a.T = 3 years 4 months = 40/12 years = 10/3 years

Find the simple interest on:(a) $ 900 for 3 years 4 months at 5% per annum. Find the amount also.Solution:P = $ 900,R = 5% p.a.T = 3 years 4 months = 40/12 years = 10/3 yearsTherefore, S.I = (P × R × T)/100 = (900 × 5 × 10)/(100 × 3) = $ 150

Find the simple interest on:(a) $ 900 for 3 years 4 months at 5% per annum. Find the amount also.Solution:P = $ 900,R = 5% p.a.T = 3 years 4 months = 40/12 years = 10/3 yearsTherefore, S.I = (P × R × T)/100 = (900 × 5 × 10)/(100 × 3) = $ 150Amount = P + S.I = $ 900 + $ 150 = $ 1050

Step-by-step explanation:

$ 1000 for 6 months at 4% per annum. Find the amount also.

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 years

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 yearsS.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 yearsS.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20Therefore, A = P + I = $( 1000 + 20) = $ 1020

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 yearsS.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20Therefore, A = P + I = $( 1000 + 20) = $ 1020(c) $ 5000 for 146 days at 15¹/₂% per annum.

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 yearsS.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20Therefore, A = P + I = $( 1000 + 20) = $ 1020(c) $ 5000 for 146 days at 15¹/₂% per annum.Solution:

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 yearsS.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20Therefore, A = P + I = $( 1000 + 20) = $ 1020(c) $ 5000 for 146 days at 15¹/₂% per annum.Solution:P = $ 5000, R = 151/2% p.a. T = 146 days

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 yearsS.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20Therefore, A = P + I = $( 1000 + 20) = $ 1020(c) $ 5000 for 146 days at 15¹/₂% per annum.Solution:P = $ 5000, R = 151/2% p.a. T = 146 daysS.I = ( 5000 × 31 × 146)/(100 × 2 × 365)

$ 1000 for 6 months at 4% per annum. Find the amount also.Solution:P = $ 1000,R = 4% p.a.T = 6 months = 6/12 yearsS.I = (P × R × T)/100 = (1000 × 4 × 1)/(100 × 2) = $ 20Therefore, A = P + I = $( 1000 + 20) = $ 1020(c) $ 5000 for 146 days at 15¹/₂% per annum.Solution:P = $ 5000, R = 151/2% p.a. T = 146 daysS.I = ( 5000 × 31 × 146)/(100 × 2 × 365)= $ 10 × 31 = $ 310

Answer 2

Answer:

Step-by-step explanation: