Question

90g of acetic acid reacts with excess of nahco3 the what volume of co2 will produce

Answer 1

Answer:

The chemical reaction will be:

NaHCO

3

+CH

3

COOH→CH

3

COONa+H

2

O+CO

2

molarmass:

NaHCO

3

=84

CH

3

COOH=60

CH

3

COONa=82

CO

2

=44

84gNaHCO

3

+60gCH

3

COOH→82gCH

3

COONa+44gCO

2

Moles of NaHCO

3

=

84

6.3

=0.075

Moles of CH

3

COOH=

60

15

=0.25

∴NaHCO

3

is the limited reagent.

Moles of CO

2

formed=0.075

weight of CO

2

=0.075×44=3.3g