Question

90ml of pure dry o2 is subjected to silent electric discharge. if only 10%of it is converted to o3 volume of mixture of gases ( o2 and o3) after the reaction will be........ and after passing through turpentine oil will be ........ . one year ago

Answer 1

The reaction of oxygen to ozone can be shown as:

$3O_2         ->          2O_3$

$Now, for 90 ml of O_2 volume of Ozone = 90*2/3 = 60 ml$

Only 10% O_3 is converted and can be shown as:

$Volume of ozone = 10 % of 60 = 6 ml.$

Hence,

AFter some time the remaining volume of ozone = 6 mL

Volume of oxygen = 90 – 6 = 84 mL

Answer 2

Answer:

87 mL & 81 mL

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