Question

91 - [22 - {16 ÷ ( 39 + 3 of 3 - 40)}]

Answer 1

Given

91 - [22 - {16 ÷ ( 39 + 3 of 3 - 40)}]

To find

The value of 91 - [22 - {16 ÷ ( 39 + 3 of 3 - 40)}]

Solution

$91 - [22 - {16\div ( 39 + 3\ \text{of}\ 3 - 40)}]\\ =91 - [22 - {16 \div( 39 + 3 \times 3 - 40)}]\\ =91-[22-16\div(39-40+3\times 3)]\\ =91-[22-16\div(-1+9)]\\ =91-[22-16\div(8)]\\= 91-[22-\dfrac{16}{8}]\\ =91-[22-2]\\ =91-20\\ =71$

Therefore, $91 - [22 - {16\div ( 39 + 3\ \text{of}\ 3 - 40)}]=71$.