Question

91. The sum of two numbers is 110. One-fifth of the larger number is 8 more than one-ninths of the
smaller number. Find the numbers​

Answer 1

$\huge\rm\underline\purple{Answer:-}$

Let the first smaller number be 'x' and the larger number be 110 - x

Let the first smaller number be 'x' and the larger number be 110 - xSo, according to the question.

Let the first smaller number be 'x' and the larger number be 110 - xSo, according to the question.(110 - x)/5 - 8 = x/9

Let the first smaller number be 'x' and the larger number be 110 - xSo, according to the question.(110 - x)/5 - 8 = x/9Taking L.C.M. and solving it, we get.

Let the first smaller number be 'x' and the larger number be 110 - xSo, according to the question.(110 - x)/5 - 8 = x/9Taking L.C.M. and solving it, we get.(110 - x - 40)/5 = x/9

Let the first smaller number be 'x' and the larger number be 110 - xSo, according to the question.(110 - x)/5 - 8 = x/9Taking L.C.M. and solving it, we get.(110 - x - 40)/5 = x/9Now, cross multiplying these, we get.

Let the first smaller number be 'x' and the = 14xx = 630/14x = 45Smaller number is 45 and the larger number is 110 - 45 = 65

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