Question

92) It point (x,y) is equidistant from
point (1, 1) & (3,5) find relation
bitueen
(2M)
*
& t​

Answer 1

Step-by-step explanation:

It point P(x,y) is equidistant from

point A(1, 1) & B(3,5)

PA= PB

PA^2= PB^2

(x-1) ^2+(y-1)^2=(x-3)^2+(y-5)^2

x^2-2x+1^2+y^2-2y+1^2=x^2-6x+3^2+y^2-10y+5^2

-2x+1-2y+1=-6x+9-10y+25

6x-2x+10y-2y-25-1=0

4x+8y-26=0

2x+4y-13=0