Question

92. The ceiling of a room is 15m 17cm long and 9m 2cm
broad. The least number of square tiles required to pave
for this is
(a) 768
(1) 814
(c) 878
(c) 898​

Answer 1

Answer:

please find it by yourself....I am sure that your teacher must have thought you

Answer 2

Answer:

814

Step-by-step explanation:

Lenght of the room=15m 17cm=

15×100+17=1517

breadth=9m2cm=902 cm

the HCF of the 1517 and 902 will be size of saure tiles

HCF 1517 and 902 = 41cm

area of room= leanth×breadth=1517×902cm²

area of tiles=41×41cm²1

so num. of tiles required(1517×902)(41×41)

=814 tiles