Question

92. The map distance between genes A and B is 3 units, between B and C is 10 units and between C and A is 7 units. The order of the genes in a linkage map
constructed on the above data would perhaps be
АВ. С
b
АС, В
B, CA
d
В. АС​

Answer 1

Answer:

Distance between A and B is 3 units. Between B and C is 10 units. Between C and A is 7 units. So it can be marked as :

B            A                             C

|------------|-------------------------|

 3 Units        7 units

please mark as brainlist