Math, asked by swarnapathak012, 6 months ago

92. Three men A, B and C working together can do a work in 6 hours
less than that of A, 1 hour less than B and half the time of C. In how
many days will A and B together finish it?
तीन पुरुष ए, बी और सी एक साथ काम करने पर ए से 6 घंटे कम बी से
1
घंटे कम और सी के आधे समयमें एक काम कर सकते है। ए और बी एक
साथ कितने दिनों में इसे खत्म करेंगे?
a) 2/3
b) 4/3,
c) 5/3
d) 7/3
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Answers

Answered by anupamasahu1974
1

Answer:

Time taken by A =x hours.

Therefore taken by A, B and C together = (x - 6)

Time taken by B = (x - 5)

Time taken by C = 2(x - 6)

Now, rate of work of A + Rate of work of B + Rate of work of C = Rate of work of ABC.

⇒1x+1x−5+12(x−6)=1x−6

On solving above equation, we get x = 3, 406

When x = 3, the expression (x - 6) becomes negative, thus it's not possible.

⇒x=406

Time taken by A & B together = 1320+35

= 43

hours

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