Question

9³×27×t⁴
upon
(3)²×(3)⁴×t²​

Answer 1

Step-by-step explanation:

(3)

−2

×(3)

4

×t

2

(9)

3

×27×t

4

=

(3)

−2

×(3)

4

×t

2

(3

2

)

3

×(3)

3

×t

4

=(3)

6

×(3)

3

×(3)

2

×(3)

−4

×t

4

×t

−2

⋯⋯[∵a

−m

=

a

m

1

]

=(3)

11−4

×t

4−2

⋯⋯[∵a

m

×a

n

=a

m+n

]

=(3)

7

×t

2

Answer 2

Answer:

ANSWER

(3)

−2

×(3)

4

×t

2

(9)

3

×27×t

4

=

(3)

−2

×(3)

4

×t

2

(3

2

)

3

×(3)

3

×t

4

=(3)

6

×(3)

3

×(3)

2

×(3)

−4

×t

4

×t

−2

⋯⋯[∵a

−m

=

a

m

1

]

=(3)

11−4

×t

4−2

⋯⋯[∵a

m

×a

n

=a

m+n

]

=(3)

7

×t

2