93. A body starts from rest and falls vertically through
a height of 19.6 m. If g =9.8 m/s2, then the time
taken by the body to fall through the last metre
of its fall is :
(a) 0.45 s
(b) 1.95 S
(c) 0.05 S
(d) 2.00 s
Answers
Answered by
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Explanation:
As the body rises from the height of 19.6m
since heighr=19.6m
Initial velocity(u)=?
Final velocity(v)=0
Acceleration(g)= -9.8m/s
Time=0
Applying
v^2-u^2=2gh
(0)^2-(u) ^2=2x(-9.8)x19.6
0-u^2= -19.6x19.6
-u^2= -384.16
-u=√384.16
-u =19.6
Applying
v=u+gt
0= –19.6–9.8xt
= –19.6=–9.8xt
–19.6/–9.8=t
=2.00s
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