Question

93. In Drosophila, two recessive genes produce white
eye and miniature wings in contrast to their wild
type, which results from the dominant alleles. The
result from the cross between heterozygous wild
type and homozygous recessive one, for both traits
are as follows
w* w m* m = 66
w* w m m = 39
w w m* m = 35
w w m m = 60
In term of cross over units, how far apart are these
two genes on the chromosome?
(1) 49 cM
(2) 37 cM
(3) 50 cM
(4) 63 cM​

Answer 1

Answer:

i think 3 is the right ans mate .......

Answer 2

In term of cross over, two genes on the chromosome are 37cM apart.

• According to these question, parental type are w*w m*m and w w m m
• Recombinant phenotype are w* w m m and w w m* m
• Formula for distance between two gene = (total number of recombinant phenotype/ total number of phenotypr)*100 cM
• Here, [(35+39)/(66+39+35+60)]*100 = (74/200)*100 =37
• Another unit for distance between two gene is mu or map unit.