Question

94. (i) CH2 = CH – CH2 – CH=CH2
(ii) CH2 = CH – CH = CH – CH3
(iii) CH3 – CH = CH – CH = CH – CH3
The numbers of possible geometric isomers for the above compounds respectively are:
(a) 0, 2, 4
(b) 2, 2, 4
(c) 0,3,3
(d) 0, 2, 3​

Answer 1

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