Math, asked by AnanyaBaalveer, 3 days ago

95. A conical cup 18 cm high has a circular base of diameter 14 cm. The cup is full of water, which is now poured into a cylinder vessel of circular base of diameter 10 cm. What will be the height of water in the vessel??​

Answers

Answered by saniasultana980
2

Answer:

Radius of the conical cup r=

2

14

=7cm and height of the cup h=18cm Therefore

Volume of water in the cup =

3

1

πr

2

h=

3

1

×

7

22

×7×7×18=924cm

3

Now radius of the circular cylinder R=

2

10

cm=5cm

Let the height of water be H centimeters Then

Volume of water =πR

2

H=

7

22

×5×5×H=

7

25×22

Hcm

This volume is equal to the volume of water poured out from the cup i.e.

7

22

×25H=924orH=

22×25

924×7

=11.76cm

∴ Height of water in the vessel =11.76 cm

Step-by-step explanation:

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Answered by xxitssagerxx
4

\huge\sf\fbox\purple{ ♡ Solution ♡ }

★ Explanation ★

Radius of the conical cup r= 214

= 7cm and height of the cup h=18cm Therefore

Volume of water in the cup = 31

πr 2 h = 31

× 722 ×7×7×18=924cm

3 Now radius of the circular cylinder R = 2 10

cm = 5cm

Let the height of water be H centimeters Then

Volume of water = πR 2

H = 722 × 5 × 5 × H =

725 × 22 Hcm

This volume is equal to the volume of water poured out from the cup i.e.

722 × 25H = 924 or

H = 22 × 25 924 × 7

=11.76cm

∴ Height of water in the vessel =11.76 cm

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