95. A tuning fork A produces 4 beats per second with another tuning fork B. It is found that by loading B with some wax, the beat frequency increases to 6 beats per second. If the frequency of A is 320 Hz, the frequency of B when loaded is (b) 316 (d) 322 (a) 324 (c) 314
with explenation
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To have 4 beats per second, f
A
can be either 316 Hz or 324 Hz.
Since filing increases the frequency, beat frequency, f=f
B
−f
A
=4 beats per second
f
A
= frequency of fork A before filing
f
A
=320−4=316 Hz
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♥*♡∞:｡.｡Answer by Shreyas｡.｡:∞♡*♥
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