Question

95. If (x + y + z) = 9 and (xy + yz + zx) = 26 then find the value of x2 + y2 + z2 = ? ​

Answer 1

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Answer 2

Answer:

using (a+b+c)²=a²+b²+c²+2ab+2bc+2ca

(x+y+z)²=x²+y²+z²+2xy +2yz +2xz

(x+y+z)²=x²+ y²+ z²+2 (xy+ yz +zx)

x²+y²+ z ²=(x+y+z)²-2(xy+ yx +zx)

x²+y²+z²=(9)²-2(26)

x²+y²+z²=81-52

x²+y²+z²=29