Question

95. Two integers are selected at random from
integers 1 to 11. If the sum is even then the

probability that both numbers are odd is​

Answer 1

Step-by-step explanation:

numbers between 1-11 are

1,2,3,4,5,6,7,8,9,10,11

sum should be even and the numbers should be odd:-

1+3=4

3+5=8

5+7=12

7+9=16

9+11=20

11+1=12

P(S)= N(E)/N(S)

= 6/11