Question

95% volume by volume H2 s o4 in given sample. find the molality of H2 s o4 . density is equal to 1.09 gram per ml​

Answer 1

Answer:

500

Explanation:

Correct option is

C

500

Given : Molarity of H

2

​

SO

4

​

 = 18M

             As,  Molarity =  

volume of solution

no. of moles of solute

​

i.e., 18moles of sulphuric acid is present per litre of solution.

            Density=1.8g/mL               {given}

Thus , mass of one litre of this solution ,

Density =  

volume

mass

​

mass = density×volume  

mass = 1.8×1000

mass = 1800g

Thus , mass of 1litre 18M H

2

​

SO

4

​

 solution is 1800g or 1.8kg.

Now, mass of solution = mass of solute + mass of solvent

         mass of solution = no. of moles of solute X molar mass of solute + mass of solvent

        1800 = 18×98 + mass of solvent

         mass of solvent = (1800−1764)g

         mass of solvent = 36g

Now , molality of H

2

​

SO

4

​

 solution is given by,

molality =  

massofsolvent(inkg)

numberofmolesofsolute

​

molality =  

36

18×100

​

 

molality = 500m  

Hence, the molality of H

2

​

SO

4

​

 solution is 500m.