Question

95 : What maximum height a stone will
reach if it is thrown upwords with a velocity
of 20m/sec?(g = 10m/sec2) at​

Answer 1

Question :

Find the Maximum height reached by the stone if it is thrown upwards with a velocity of 20 m/s. ( Take g = 10 m/s²)

Given :

• Initial velocity of the stone = 20 m/s
• Acceleration due to gravity = 10 m/s²

To find :

• Maximum height reached by the stone

Solution :

Maximum height reached when the stone is thrown upwards is given by ,

$\dag {\boxed {\rm{ \: h = \frac{ {u}^{2} }{2g} \: }}}$

We have ,

• u = 20 m/s
• g = 10 m/s²

By substituting the values ,

$: \implies \rm \: h = \dfrac{(10) {}^{2} }{2(10)} \\ \\ : \implies \rm \: h = \frac{100}{20} \\ \\ : \implies \rm \: h = \frac{ \cancel{100}}{ \cancel{20}} \\ \\ : \implies \rm \: h = 5 \: m$

∴ The Maximum height reached by the stone when it is thrown vertically thrown with a velocity of 20 m/s and g as 10 m/s² is 5m.