Question

95 What maximum height a stone will
reach if it is thrown upwords with a velocity
of 20m/sec?(g = 10m/sec2)| कसी पत्थर की
अ धकतम ऊंचाई क्या होगी यदि उसे 20
मीटर सेकण्ड (GB1om/sec2) के वेग से ऊपर
की ओर फेंका जाए?
A : 10m 10 मी
B B 20m 120 मी
30m130 मी
40m|40 मी​

Answer 1

Answer:

• Maximum height a stone will reach = 20 m

Step-by-step explanation:

Given that:

• A stone is thrown upwords with a velocity of 20 m/sec.

To Find:

• Maximum height a stone will reach.

Formula used:

• v² - u² = 2gh

Where,

• Initial velocity is denoted as v.
• Final velocity is denoted as u.
• Acceleration due to gravity is denoted as g.
• Maximum height/displacement is denoted as h.

We have:

• Initial velocity = 20 m/sec
• Final velocity = 0 m/sec [At maximum height]
• Acceleration due to gravity = 10 m/sec² [Given]

Finding the maximum height:

⇒ v² - u² = 2gh

⇒ 20² - 0² = 2 × 10 × h

⇒ 400 = 20h

⇒ h = 400/20

⇒ h = 20

∴ Maximum height a stone will reach = 20 m

Answer 2

Given :-

• Velocity = 20 m/s
• G = 10 m/s

To Find :-

Maximum height reached

Solution :-

We know that

$\sf v^{2} - u^{2} = 2gh$

$\sf 20^{2} - 0^{2} = 2(10)h$

400 - 0 = 20h

400 = 20h

h = 400/20

h = 20 m