Question

96-10a+15 and 3a+b+2, Add the given terms.

Answer 1

BONJOUR,
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$(96 - 10a + 15) + (3a + b + 2) \\ 96 - 10a + 15 +3a + b + 2 \\ = 96 + 15 + 2 - 10a + 3a + b \\ = 113 - 7a + b$

Answer 2

Solution :

Given two expressions are ,

96 - 10a + 15 and 3a + b + 2

Addition of these expressions

= ( 96-10a +15 )+ ( 3a + b +2 )

= -10a + 3a + b + 96 + 15 + 2

= ( -10 + 3 )a + b + 113

= -7a + b + 113

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