Question

96-4x-x^2 factorise ​

Answer 1

Step-by-step explanation:

$- {x}^{2} - 4x + 96$

$= - {x}^{2} - 12x + 8x + 96$

$= - x(x + 12) + 8(x + 12)$

$= ( - x + 8)(x + 12)$

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Answer 2

Answer:

x ² + 4x + 96 = 0

Use the quadratic formula

=−± square root 2−4/ 2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2+4+96=0

x^{2}+4x+96=0x2+4x+96=0

=1

a={\color{#c92786}{1}}a=1

=4

b={\color{#e8710a}{4}}b=4

=96

c={\color{#129eaf}{96}}c=96

=−4±42−4⋅1⋅96√2⋅1

2

Simplify

Evaluate the exponent

Multiply the numbers

Subtract the numbers

Multiply the numbers

=−4±−368√2

3

No real solutions because the discriminant is negative

The square root of a negative number is not a real number

=−368