Question

96. A force F= (5i-3j+2k) N moves a particle from r1 = (2i+7j + 4k ) to
r2=(5i+2j + 8k)m. The work done by
the force is 10
(1) 18J
(2) 28J
(4) 48J
(3)38J​

Answer 1

Given:

• Force = (5i - 3j + 2k) N

• Displacement = r2 - r1

• Displacement = (3i - 5j + 4k) m

To find:

→ Work done by the force.

Solution:

• Work = Force . Displacement

» Work = (5i - 3j + 2k) . (3j - 5j + 4k)

» Work = 15 + 15 + 8

» Work = 38 J

Therefore, work done is 38 J.

Answer 2

Answer:

38j

Explanation: