Question

96 abc (3a-12) (5b-30 ) divided 144 (a-4)(b-6)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

 $\frac{96abc(3a-12)(5b-30)}{144(a-4)(b-6)}$ $=10$  

Step-by-step explanation:

Given : $\frac{96abc(3a-12)(5b-30)}{144(a-4)(b-6)}$

To find : The value of above equation.

Solution :

• The given equation is,  

         $\frac{96abc(3a-12)(5b-30)}{144(a-4)(b-6)}$

• We have to find the value of above equation.
• In this division, the dividend is $96abc(3a-12)(5b-30)$ and divisor is $144(a-4)(b-6)$.

• So, solving the division, we get

        $\frac{96abc(3a-12)(5b-30)}{144(a-4)(b-6)}$ $= \frac{96abc*3(a-4)*5(b-6)}{144(a-4)(b-6)}$

                                = $\frac{1440(a-4)(b-6)}{144(a-4)(b-6)}$

• Now, cancelling the common terms and brackets from numerator and denominator, we get

                                = $10$

• ∴ The value of   $\frac{96abc(3a-12)(5b-30)}{144(a-4)(b-6)}$ $=10$