Question

96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part ?

Answer 1

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Here is your answer.
Let the one part is x
and other part is (96-x)

ATQ
$\frac{x}{7} = \frac{96 - x}{9} \\ 9x = 96 \times 7 - 7x \\ 9x + 7x = 672 \\ 16x = 672 \\ x = \frac{672}{16} \\ x = 42$
So one part is 42
and other part is
$= 96 - 42 \\ = 54$
Hence the smallest part is 42
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