97, 102, 107, 112... is an arithmetic progression 1)find 15th term in this series 2)what is its nth term 3)find sum of 50 terms in this series
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Step-by-step explanation:
a=97
d=5
now,
1. 15th term= a+(n-1)d
= 97+(14)5
= 167. [ans]
2. nth term= a+(n-1)d
= 97+(n-1)5
= 97+5n-5
= 92+5n. [ans]
3. sum of 50 terms= n/2[2a+(n-1)d]
= 25[194+(49)5]
= 25(194+245)
= 25(439)
= 10975. [ans]
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