(97×102) simplify using suitable Identity
Answers
Answered by
9
there must be 98 not 97. if it is 97 it can't be solved
(100-2)×(100+2)
using (a+b)×(a-b)=a^2-b^2
100^2-2^2
10000-4
9996
(100-2)×(100+2)
using (a+b)×(a-b)=a^2-b^2
100^2-2^2
10000-4
9996
kunal0404:
100-2 is 98 . Your answer is wrong
Dear, it is no possible that their is 97 and 102 if it is so it cannot be solved.
No bro , it can be solved . Check my answer .
There is one more identity for this question that is : (x+a) (x+b) = x^2 (a+b)x + (ab) . Check it on google or in 9th ncert .
There is one more identity for this question that is : (x+a) (x+b) = x^2 (a+b)x + (ab) . Check it on google or in 9th ncert .
yes you are right. sorry for that please report my answer
Also multiply the numbers without using identity. The answer will be same as mine .
No prob bro , Just correct it . No need of reporting.
there is no option.
Not here . Correct it in further question. Don’t repeat the same mistake .
Answered by
31
(100-3) (100+2) = (100)^2 + (-3+2)(100) + (-3*2).
By identity (x+a) (x+b) = x^2+ (a+b)x + (ab)
=9894
By identity (x+a) (x+b) = x^2+ (a+b)x + (ab)
=9894
Thanx
Wc
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