Question

97. Find the value of
(2-a) 3+(2-b)3+(2-c)3 -3(2-a)(2-b)(2-c)
when a + b c = 6​

Answer 1

Step-by-step explanation:

If x + y +z =0 then x(cube)+y(cube)+z(cube)-3xyz=0

therefore, if x = 2-a ; y = 2-b ; z = 2-c

then x+y+z i.e., 2-a+2-b+2-c=0.this implies that a+b+c=6

then x(cube)+y(cube)+z(cube)-3xyz=0 i.e,

(2-a)3+(2-b)3+(2-c)3-3(2- a)(2-b)(2-c) = 0