Question

98^2*82^2=3x*2y*5z find x y z

Answer 1

Answer:

Step-by-step explanation:

2  

x

×3  

y

×5  

z

=2160,  

2160=2×2×2×2×3×3×3×5

2160=2  

4

×3  

3

×5  

1

 

by comparision, we get,

x=4,y=3,z=1

3  

x

×2  

−y

×5  

−z

 

=3  

4

×2  

−3

×5  

−1

 

=  

2  

3

×5

3  

4

 

​

 

=  

40

81

​

Answer 2

Answer:

x = 2

y = 1

z = 6

Step-by-step explanation:

$98^{2}$ - $82^{2}$ = (98-82)(98+82)

              = 16*180

              = 2880

Prime factorization of 2880 = 2*2*2*2*2*2*5*3*3

$3^{2}$ = 9

$5^{1}$ = 5

$2^{6}$ = 64

and 9*5*64 = 2880

Hence proved