Question

98.

A box contains 19 balls bearing numbers 1, 2, 3, ..., 19 respectively. A ball is drawn at random from the box. Find the probability that the number on the ball is a number divisible by 3.​

Answer 1

Answer:

Total number of possible outcomes = 19 (i) Prime numbers are 2, 3, 5,7 , 11, 13, 17 , 19. .'. Probability of numbers being prime = 8/19 (ii) Numbers divisible by 3 or 5 are 3, 5, 6, 9, 10, 12, 15, 18. .'. Required probability = 8/19 (iii) Numbers neither divisible by 5 nor by 10 are 1 , 2, 3, 4,6, 7, 8, 9, 11 , 12, 13, 14, ,16, 17 , 18,Read more on Sarthaks.com - https://www.sarthaks.com/252794/a-box-contains-19-balls-bearing-numbers-1-2-3-19Required probability = 16/19 (iv) Even numbers are 2, 4, 6, 8, 10, 12, 14, 16, 18. .'. Required probability = 9/19Read more on Sarthaks.com - https://www.sarthaks.com/252794/a-box-contains-19-balls-bearing-numbers-1-2-3-19

Step-by-step explanation:

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