98 gms of CH3COOK was dissolved in to make a solution of 0.5 liters? find the molarity?
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Molecular Mass Of CH3COOK
= 12+3×1+12+2×16+39
= 98 g/mol
Number Of Moles Of CH3COOK
= mass of CH3COOK /molecular mass of CH3COOK
=98/98
= 1 mol
Molarity = number of moles of CH3COOK / volume of CH3COOK (in litres)
= 1/0.5
= 2 m
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