98 POINTS QUESTION!!!!
a) factorise x⁴ + 125xy³
b) simplify (p -2q +3r)² - (p + 2q - 3r)²
Answers
Answered by
3
a) x^4 + 125xy^3
= x(x^3 + 125 y^3)
b) (p - 2q + 3r)^2 - ( p + 2q - 3r)^2
= p^2 + 4q^2 + 9r^2 - p^2 - 4q^2 - 9r^2 )
= p^2 - p^2 + 4q^2 - 4q^2 + 9r^2 - 9r^2
= 0
Hope it helps.
= x(x^3 + 125 y^3)
b) (p - 2q + 3r)^2 - ( p + 2q - 3r)^2
= p^2 + 4q^2 + 9r^2 - p^2 - 4q^2 - 9r^2 )
= p^2 - p^2 + 4q^2 - 4q^2 + 9r^2 - 9r^2
= 0
Hope it helps.
yuvikagupta:
I'm sorry
kindly correct both answers
whats wrong with the second answer
sorry i think i just found the mistake
OK OK fine guys
Jst chill
it's fine.. thanks anyways :)
I'm just deleting it
is that ok
I think it is
Answered by
3
(a)
Given : x^4 + 125xy^3
= > x(x^3 + 125y^3)
= > x((x)^3 + (5y)^3)
= > x(x + 5y)(x^2 + 5^2y^2 - 5xy)
= > x(x + 5y)(x^2 + 25y^2 - 5xy).
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(b)
Given : (p - 2q + 3r)^2 - (p + 2q - 3r)^2
= > (p - 2q + 3r)(p - 2q + 3r) - (p + 2q - 3r)(p + 2q - 3r)
= > p^2 - 4pq + 6pr + 4q^2 - 12qr + 9r^2 - p^2 - 4pq + 6pr - 4q^2 + 12qr - 9r^2
= > -8pq + 12pr
Hope this helps!
Thanks!
welcome!
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