Math, asked by a5508621, 1 year ago

98 POINTS QUESTION!!!!

a) factorise x⁴ + 125xy³
b) simplify (p -2q +3r)² - (p + 2q - 3r)²

Answers

Answered by yuvikagupta
3
a) x^4 + 125xy^3
= x(x^3 + 125 y^3)

b) (p - 2q + 3r)^2 - ( p + 2q - 3r)^2
= p^2 + 4q^2 + 9r^2 - p^2 - 4q^2 - 9r^2 )
= p^2 - p^2 + 4q^2 - 4q^2 + 9r^2 - 9r^2
= 0

Hope it helps.

yuvikagupta: I'm sorry
siddhartharao77: kindly correct both answers
a5508621: whats wrong with the second answer
a5508621: sorry i think i just found the mistake
yuvikagupta: OK OK fine guys
yuvikagupta: Jst chill
a5508621: it's fine.. thanks anyways :)
yuvikagupta: I'm just deleting it
yuvikagupta: is that ok
yuvikagupta: I think it is
Answered by siddhartharao77
3

(a)

Given : x^4 + 125xy^3

= > x(x^3 + 125y^3)

= > x((x)^3 + (5y)^3)

= > x(x + 5y)(x^2 + 5^2y^2 - 5xy)

= > x(x + 5y)(x^2 + 25y^2 - 5xy).

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(b)

Given : (p - 2q + 3r)^2 - (p + 2q - 3r)^2

= > (p - 2q + 3r)(p - 2q + 3r) - (p + 2q - 3r)(p + 2q - 3r)

= > p^2 - 4pq + 6pr + 4q^2 - 12qr + 9r^2 - p^2 - 4pq + 6pr - 4q^2 + 12qr - 9r^2

= > -8pq + 12pr

Hope this helps!


a5508621: Thanks!
siddhartharao77: welcome!
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