Question

98 POINTS QUESTION!!!!!

FACTORISE

(p - 3q)³ + (3q - 7r)³ + (7r - p)³

Answer 1

here, a+b+c=0
so ,
${ a}^{3} + {b}^{3} + {c}^{ 3} = 3abc$
so,
3(p-3q)(3q-7r)(7r-p)
(3p-9q)(2q-7r)(7r-p)
Attachment available please find next steps in it.
thats your answer!!!!
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Answer 2

Hey dude!!

Here's the correct answer

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Let , a = ( p - 3q ) , b = ( 3q - 7r ) , c = ( 7r - p )

If , ( a + b + c ) = 0

Then , a^3 + b^3 + c^3 = 3abc

↑ Using this identity,

( p - 3q )^3 + ( 3q - 7r )^3 + ( 7r - p )^3

= 3 × ( p - 3q ) ( 3q - 7r ) ( 7r - p )

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Hope it helps you!!