Question

98 POINTS QUESTIONS!!

a) Find mean, median and mode of all factors of 100
b) ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. Show that AE and EC bisects diagonal BD.

(At least answer one question, really urgent!!)

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!!}}}$

$<b>$a) Factors of 100

= 1,2,4,5,10,20,25,50,100

Median = 10 (as it is the middle most value)

Mode = 100 (as it is the highest value)

Explaination:

Mode is the number which occurs the maximum number of times but if there is no mode, so the mode will be the highest value.

$mean = \frac{sum \: of \: all \: observations}{number \: of \: observations} \\ \\ = \frac{1 + 2 + 4 + 5 + 10 + 20 + 25 + 50 + 100}{9} \\ \\ = \frac{220}{9} \\ 24.44$

b) answer in the attachment:-)


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Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!!}}}$

$<b>$ As you have given, I will answer only one part.

a) Factors of 100
1, 2, 4, 5, 10, 20, 25, 50, 100.

Mean =
$\frac{sum \: of \: all \: observations}{number \: of \: all \: observations}$
$= \frac{1 + 2 + 4 + 5 + 10 + 20 + 25 + 50+100}{9}$

$= \frac{217}{9} \\ = 24.11$
Median = 10 ( as it is the middle most value)

Mode = 100 ( as mode is the highest occurring value but if there is none, then the highest value is the mode).

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