98. the amplitude of simple pendulum
is 4x10-2m. The KE and PE will
equal at a distance from the
equilibrium position of
1) Ix10-2m 2) 2x10-2m
3) 272x10-ºm 4) 12x10-'m
Answers
Answered by
3
The answer is 2 × 10-²m
amplitude is maximum displacement or distance moved by a point on vibrating body or waves measure from its equilibrium positions
so,
here maximum distance or displacement is
4 × 10-²m
so equilibrium ( equal ) of Kinetic energy and potential energy will be at 2 × 10-²m.
if you think my answer is wrong then you can report .....
Similar questions