Question

98. Three particles are placed at corners of an
equilateral triangle. Find moment of inertia of
system of particles about y axis

1) 1/2 ml^2
2) 1/4 ml^2
3) 3/2 ml^2
4) 3/4 ml^2

​

Answer 1

Answer:

ml

2

The angle is given as,

sinA=

l

d

sin30

∘

=

l

d

d=

2

l

The moment of inertia about the axis AX is given as,

I

AX

=ml

2

+md

2

=ml

2

+m(

2

l

)

2

=

4

5ml

2

Thus, the moment of inertia about the axis 1 is

4

5ml

2

.