Question

98% (w/w) h2so4 has density 1.84 m. calculate its molarity. molar mass of h2so4=98 g mol^-1.

Answer 1

Molarmass-98g/mole w/w=98%density =1.84 v=1000m mass=V*D=1000*1.84=1840 98%of H2SO4-1840g=98/100*1840=1803.2m moles=m/Mm=1803.2/98=1.84 M ds molarity=1.84M

Answer 2

Given:

Density = 1.84m

Weight of $H_2SO_4$ = 98g

Weight of solution = 100g

To find:

Molarity = ?

Formula to be used:

1. Number of moles = $\frac{Given mass}{Molar mass}$
2. Molarity = $\frac{number of moles}{Volume}$

Calculation:

Volume of the solution = $\frac{mass}{density}$ = $\frac{100}{1.84}$ = 54.3 $cm^3$

Weight of the solvent = 100 - 98 = 2g

Molecular weight of $H_2SO_4$ = 98g/mol

∴ No. of moles in 98g = $\frac{Given mass}{Molar mass}$ = $\frac{98}{98}$ = 1 mol

Molarity =  $\frac{number of moles}{Volume}$ × 1000

Molarity = $\frac{1}{54.3}\times 1000$

Molarity = 18.41 mol

Conclusion:

Thus the molarity of the solution is calculated as 18.41 mol/L.

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